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Problem

A total of 600 C of charge passes through a flash…

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Problem 1 Easy Difficulty

What is the current in milliamperes produced by the solar cells of a pocket calculator through which 4.00 C of charge passes in 4.00 h?

Answer

$I=0.278 \mathrm{mA}$

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02:19

Manish H.

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Physics 102 Electricity and Magnetism

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Chapter 20

Electric Current, Resistance, and Ohm's Law

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Video Transcript

So this is Ah, simple problem. What? We want to calculate the current in million that, um, is produced by the solar cells of a pocket calculator through which, um, 4.0 Coolum of charge passes in four hours. So most of the problem here is just actually doing, you know, conversion here because we know an amp is a cool, um, per second so And I am measures. How many cool OEMs are? Charges are passing by some plain in a one second. Um, so we know how many. And we'll assume that you know, the everything is uniformed here, the flow of charges. Uniforms over this four hours, or at least this will give us the average current, um, that flowed. So the change in time then is four hours, but we need to convert that the second. So that's 14,400 seconds that a total amount of charge that flowed waas um, 4.0 cool loans. So the current and I should probably maybe put a bar over here to know, you know, that it's an average current. So this is the the average current over that four hours, um, is the charge that passed that went through the calculator or came out of the solar cells divided by the time so that simply that and doing the algebra we get 0.278 times, 10 to the minus three coup loans per second. Um, a coolant per second is an ampere. And if we wanted in million piers, then we can get rid of this, um, 10 to the minus third. So in the end, we wind up with an answer of 0.278 million apps, Um, or million piers and again. So it's basically simply a, you know, like calculating the velocity of charges. Right. So how much charge? Um, um, passed by over Over what? Period of time. So they went by. We had 44 columns of them go by in, uh, 14,400 seconds, which gives us a current electrical current of 0.278 million

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