Question
What is the de Broglie wavelength of a basketball of mass $0.50 \mathrm{~kg}$ when it is moving at $10 \mathrm{~m} / \mathrm{s}$ ? Why don't we see diffraction effects when a basketball passes through the circular aperture of the hoop?
Step 1
The de Broglie wavelength is given by the formula: λ = h / p where λ is the de Broglie wavelength, h is the Planck's constant (6.626 x 10^-34 Js), and p is the momentum of the object. The momentum of the basketball can be calculated using the formula: p = m * Show more…
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