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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63

Problem 2 Easy Difficulty

What is the difference between the hybridization of carbon atoms’ valence orbitals in saturated and unsaturated hydrocarbons?

Answer

Alkynes contain one or more triple bonds between carbon atoms that is carbon atoms are linked
by one sigma bond and two pi bonds. In alkyne, the hybridization of carbon atoms'valence
orbital involved in triple bond is sp and it is bonded to two other atoms, one is carbon and other
can be hydrogen or carbon.

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Video Transcript

so completely saturated hydrocarbons essentially are just uh molecules without kinks and their chains. So mainly for saturated hydrocarbons, all the carbon atoms have to be sp three hybridized. So sp three hybridized, essentially all of the orbital's R. Sp three hybridized in the following and an unsaturated hydrocarbons. You can either have sp two hybridization or sp hybridization. So, for example, you can have an al keen and essentially you have double bonds that form from a new hybridized P. Or bills in Sp two. And similarly, you have trouble bonds that form from two sets, oven hybridized pure bills and as uh unharnessed pr bills. While the sp orbital's form the sigma bond. And for sp two or bills, it also forms the sigma bonds. So mainly for unsaturated hydro hydro carbons, you're going to have a new hybridized pure bills. While unsaturated hydrocarbons, you're not going to have, you're not going to have a new hybridized pure bubbles. And this gives our final answer

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Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson

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