00:01
So while seeing the question let's put a move to the answer so let's see here that the first one is coronate equation which is pi 1 is equal to p minus mc q1 so here is pi 1 is equal to 150 minus q1 minus q 2 minus 60 q 1 so pi 1 is equal to 150 minus 60 minus q2 so q1 minus q1 is squared so pi 1 is equal to 90 minus q2 so q1 minus q1 to the power 2 so br br1 so do you pi 1 by do you q1 is equal to 90 minus q2 minus 2 q1 is equal to 0.
01:49
So q1, br is equal to 90 minus q2 by 2.
01:59
So similarly, q2, br is equal to 90 minus q1 by 2.
02:17
So solving to b r 2 q1 is equal to 90 minus 45 minus 0 .5 q1 so 2 q1 is equal to 45 plus 0 .5 q1 so 1 is equal to 45 plus 0 .5 q1 so 1 .1 is equal to 45 so thus q1 is equal to to q2 is equal to 45 by 1 .5 is equal to 30 so q1 q2 is equal to 30 30 and the second one is starkler's equation so f1 move first so max pi 1 s t q2 b r so pi 1 is equal to 90 minus q 2 br so q1 minus q 1 to the power 2 which is equal to 90 minus 45 minus 5 q 1 so q 1 minus q 1 to the power 2 so pi 1 minus q 1 minus q 1 to the power 2 so pi 1 is equal to 45 plus 0 .5 q1, q1 minus q1 to the power 2 which is equal to 45 q1 minus 0 .5 q1 to the power 2.
05:26
So do you, pi 1 by 2 u, q1 is equal to 45 minus q1 is equal to 0.
05:49
So q1 sl is equal to 45 and q2 sf is equal to 45 by 2 is equal to 22 .5.
06:12
So so iso pi curve so pi 1 is equal to 45 to the power 2 minus 0 .45 to the power 2 is equal to 100012 .5 so then iso pi curve is equal to 112 .5 is equal to 90 minus q2 q1 minus q1 to the power 2 so in start berg equation is o curve of fum 1 is tangent to b r 2 so here is the full solution of the equation that so the first point is score not equation so pi 1 is equal to p minus m c q 1 5 1 is equal to 150 minus q 2 minus 6t so q 1 5 1 is equal to 150 minus 60 minus q 2 so q 1 minus q 1 to the power 2 so pi 1 is equal to 90 minus q 2 so q 1 minus power 2 so b r 1 so do you pi 1 by do you q1 is equal to 90 minus q 2 minus q 1 is equal to 0 so q 1 br is equal to 90 minus q 2 by 2 similarly q 2 br is equal to 90 minus q 1 by 2 solving to br 1 2 q 1 is equal to 90 minus 45 minus 0 .5 q1 so 2 q1 is equal to 45 plus 0 .5 q1 so 1 .5 q1 is equal to 45 thus q1 is equal to 45 by 1 .5 is equal to 30 so q1 comma q2 is equal to 30.
09:21
So the second point is a star is starkle birth equation f1 move first so max pi1 s plus q2 br so pi 1 is equal to 90 minus q2 br so q1 minus q1 to the power 2 which is equal to 90 minus 45 minus 0 .5 q1 so q1 minus q1 to the power 2 so 5 1 is equal to 45 plus 0 .5 q1 so q1 minus q1 to the power 2 which is equal to 45 q1 to the q1 to the power 2 so do you pi 1 by do you q1 is equal to q1 is equal to 0...