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What is the emf $_{\mathrm{X}}$ of a cell being measured in a potentiometer, if the standard cell's emf is 12.0 $\mathrm{V}$ and the potentiometer balances for $R_{\mathrm{x}}=5.000 \Omega$ and $R_{\mathrm{s}}=2.500 \Omega$ ?
$24 \mathrm{v}_{6} \mathrm{u}-$
Physics 102 Electricity and Magnetism
Chapter 21
Circuits, Bioelectricity, and DC Instruments
Direct-Current Circuits
Rutgers, The State University of New Jersey
University of Washington
University of Winnipeg
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so we can simply use the formula given in the textbook to solve this part. The M F X is equal to a M F s times our eggs divided by artists. This is equal to 12 times five divided by 2.5. This will be able to 24 vote. So concept of potential meter is that we was not potential or not current to sense the unknown the IMF. So the external battery source is connected here and there is a gallon of meter here and the location off this trip is adjusted such that no current flows through the galvan Amita that his I g is equal to zero. So when we make this connection on, I'd use equal to zero. This means that the potential let's say this is this is a known a battery. This is yes and is it? This is 12 old. So this is positive for the world 12 volt on dhe. This is zero. So that yes cannot give out any extra current because they are at equal potential. So if there is equal potential, different or all, the potential difference is zero local inflows on DDE. Once we know this section are ex So in this case it will not be rx. This will be our guest. We find this out so that this current is I High times are must be equal to the office. Similarly, now we replace this with e x on DDE We find this point of contact where I Jerious zero again and we find that high times our ex is the value of X And then we take a ratio here to get this formula. So the battery that we are reading is 24 world. Thank you.
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