00:01
To find the energy of the photon that is required to make this transition, we can use the equation that says that the energy required of the photon e is equal to negative 13 .6 electron volts, which comes from the ground state energy of hydrogen, multiplied by the ratio of 1 over the final orbital level, n -sub -f.
00:28
So in our case, this would be 5.
00:29
So this is n -s -f squared, minus 1 -1.
00:37
Over n sub i squared, which in part a we're told us two.
00:44
Plugging these values in, we find that the energy of the photon that is required is equal to 2 .86 electron volts.
00:58
For part b, we're going to do the exact same process, except for this time, we're going between the n equals 4 and n equals 6 orbital.
01:08
So once again, we have the same equation.
01:10
Not a bad idea to write it out again...