Question
What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of $\mathrm{ICl}$ was $0.78 \mathrm{M}$ ? $2 \mathrm{ICl}(\mathrm{g}) \rightleftharpoons \mathrm{I}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) ; \quad K_{\mathrm{c}}=0.14$
Step 1
The initial concentration of $\mathrm{ICl}$ is given as $0.78 \mathrm{M}$, and since the reaction has not yet occurred, the initial concentrations of $\mathrm{I}_{2}$ and $\mathrm{Cl}_{2}$ are both $0$. Show more…
Show all steps
Your feedback will help us improve your experience
Shazia Hussain and 71 other Chemistry 102 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An equilibrium mixture of the following reaction has $\left[\mathrm{I}_{2}\right]=0.0112 \mathrm{M}$ and $\left[\mathrm{Cl}_{2}\right]=0.0155 \mathrm{M}$ at $25^{\circ} \mathrm{C} .$ What is the concentration of ICl? $$ \begin{array}{c} \mathrm{I}_{2}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{ICl}(g) \\ K_{\mathrm{eq}}=81.9 \mathrm{at} 25^{\circ} \mathrm{C} \end{array} $$
At a certain temperature, the equilibrium constant, Kc, equals 0.11 for the reaction: 2 ICl(g) ⇌ I2(g) + Cl2(g). What is the equilibrium concentration of ICl if 0.45 mol of I2 and 0.45 mol of Cl2 are initially mixed in a 2.0-L flask? a) 0.17 M b) 0.14 M c) 0.34 M
At a certain temperature the equilibrium constant $\left(\mathrm{K}_{\mathrm{C}}\right)$ equal $0.11$ for the reaction $$ 2 \mathrm{ICl}(\mathrm{g}) \rightleftharpoons \mathrm{I}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) $$ What is the equilibrium concentration of $\mathrm{ICl}$ if $0.75$ mol of $\mathrm{I}_{2}$ and $0.75$ mol of $\mathrm{Cl}_{2}$ are initially mixed in a $2.0$ litre flask? a. $0.45 \mathrm{M}$ b. $1.45 \mathrm{M}$ c. $0.14 \mathrm{M}$ d. $0.90 \mathrm{M}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD