00:01
Hi, in the given problem there is a circuit diagram between the terminals a and b.
00:10
The diagram is as given.
00:17
This is the resistance of 42 -on.
00:24
Then two resistors are joined with it in parallel combination one is having a value of 30 om another is having a value of 45 om this is a parallel combination then another resistance having a value of 40 om is joined overall in parallel with all these resistors in left and finally this is the terminal b we have to find the net resistance of this combination.
01:01
So first of all, these two resistors having the values of 30 and 45 om are in parallel.
01:12
So the value of these resistors in parallel will be given as 30 om multiplied by 45 om divided by their sum which is 30 om plus 45 om.
01:27
As this is the rule of parallel combination if only two resistors are in parallel, r1 and r2.
01:35
If are in parallel, then their parallel combination will be given as r1 into r2 means their product in the numerator and their addition in the denominator.
01:47
So using this rule just for the two resistors in parallel, we find the value of this parallel combination and here this value, comes out to be 18 om.
02:02
So now if we make an equivalent circuit diagram, this 42 om now is in series with 18 om and this 42 and 18 om now are in parallel with 40 om...