what-is-the-frequency-of-the-third-harmonic-standing-wave-in-an-open-tube-with-a-length-of-05-mathrm

Question

What is the frequency of the third harmonic standing wave in an open
tube with a length of 0.5 $\mathrm{m}$ ? The speed of sound in the tube is 343
$\mathrm{m} / \mathrm{s}$ .
(A) 514.5 $\mathrm{Hz}$
(B) 1029 $\mathrm{Hz}$
(C) 2058 $\mathrm{Hz}$

Salamat Ali · Accepted Answer

frequencies for any harm. Weeks is given by if end Elizabeth in, uh, he derided by before l l is the length off pipe and is the harmonics for our morning squeeze the speed of sound then for 1/3 harmonic with three will be in movie three times the speed of sound off 343 divided by four times off L which is 0.5 then Simply find this expression gives us the frequency. Third harmonics is five one 4.5. So the right answer is but a

Mayukh Banik · Answer

the fundamental frequency is given by the over so well. It was 34 before middle per second, divided by two times the dentist, 0.672 meter. So that comes out to be 256 course. So the frequency of the second harmonic is twice the fundamental. It was two times 2 56 hearts. It was fine while too, for us.

Rachel Wellington · Answer

everyone. This is question number 42 from Chapter 17 and this problem. We&#x27;re given a 0.672 meter long tube open at both ends, and the speed of sound is 344 meters per second grass to find a the fundamental frequency and be the frequency of its second harmonic, so went ahead and wrote the equation for frequency through a tube open at both ends. That&#x27;s f equals envy over to L. A. And then here is the frequency that you want. The numbers of the 1st 2nd 3rd and obviously per part a fundamental frequency is another North, another name for residents structure. Excuse me, Reggie Resident&#x27;s frequency, which is the first frequency. So that and it&#x27;s just gonna be one. So for a we have F equals one times V 344 meters per second over too times L, which is the 0.672 meters. And when you plug that into a calculator, you get 256 hertz. It&#x27;s now we go on to Part B, which is the second harm Second harmonic. So that&#x27;s gonna be F equals two times 344 meters per second over two times the length and you might have already guessed it. It&#x27;s just gonna be double and that&#x27;s 512 hurts.

Farnaz Mohseni · Answer

when we have a tube with only one and open The fundamental frequency is given by dis equation V over four times out, and this is one end open. And if you have a two bit, both ends open. The fundamental frequency is given by V over two times out. So this is in a tube with both, it&#x27;s open. So from here, you can see that if one over of prime one is vey over for l divided by V over two times out. So if you can sell out, we hands l you see that if one or a private one is 1/2, so f prime one is two times F one and if one is given, chosen the question. So we know that Prime wanted equal to two times if one is 130.8 hertz. So this is equal to 261.6 hurts in the next part. We want to find the length of the two. So since one is equal to be over four times and ah, we can say l is a call to V over four times F one and V is 343 meter per second, divided by four times if one is 130 point a, so this would be equal to 0.656 leaders.

Farnaz Mohseni · Answer

so in a tube with only one and open the end. Harmonic frequency is given by N times V over four l and in this kind of too, and can only be up numbers 135 and so on. So the next frequency needs to be f n plus two or N plus two times V over for l eso here I&#x27;m going to find the ratio of its being f n plus two and and And this is equal to and plus two times V over for l divided by n times V over four l. So the over for l cancels out, we end up it and plus two over. And so we have, uh, and plus two. And we have f n and we can say 750 hertz divided by 450 Hertz is equal to and plus two divided by m. And from here we can find and to be three. So since f n. Waas 450 hertz, it means that if three is 450 hurts so off 450. Here&#x27;s response to the third harmonic, and in the next part we want to find the length of the truth. So as we said, if three should be three times V over four and l is three V over four F three, we found at three in the last part. So this is 3/4 343 meter per second, divided by 450 hurts, and I&#x27;m here refined l to be easier 0.57 wieners.

Averell Hause · Answer

So here we know that the angular frequency is Equalling to two pi times the frequency. We also know that for a pipe with one closed and we can say that the wavelength would be equaling 24 times the length of the pipe divided by n the harmonic. Now here we have the first overtone and the first overtone for a pipe with one closed end. This corresponds to the third harmonic and so we can say that then the wavelength would be equaling 24 times the length of 1.5 meters. This would be divided by three and this is giving us than two meters. The frequency of the wave F is then going to be Equalling to the velocity or the speed of propagation for the wave divided by the wavelength. This is equaling 2 340 meters per second, divided by two meters, giving us 170 hurts. We can then say that omega the angular frequency would be two pi times the frequency or two pi radiance multiplied by 170 hurts. And this is giving us 340 pie radiance for a second. And so this would be option D. That is the end of the solution. Thank you for watching

Problem

A) $\mathrm{NO} \mathrm{CHANGE}$ $\mathrm{B}$ ) …

Problem 40 Medium Difficulty

What is the frequency of the third harmonic standing wave in an open
tube with a length of 0.5 $\mathrm{m}$ ? The speed of sound in the tube is 343
$\mathrm{m} / \mathrm{s}$ .
(A) 514.5 $\mathrm{Hz}$
(B) 1029 $\mathrm{Hz}$
(C) 2058 $\mathrm{Hz}$

Answer

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