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What is the half-life for the first-order decay of carbon$(_{6}^{14} {C} \longrightarrow^{14}_{7} {N}+{e}^{-})$ The rate constant for the decay is $1.21 \times 10^{-4}$ year $^{-1}$

5727.27 years

Chemistry 102

Chapter 12

Kinetics

Carleton College

University of Maryland - University College

University of Kentucky

Brown University

Lectures

22:42

In probability theory, the…

04:55

In chemistry, kinetics is …

02:02

What is the half-life for …

00:47

The half-life of carbon-14…

02:21

(I) ($a$) What is the deca…

03:17

The rate constant for the …

02:04

(I) $(a)$ What is the deca…

05:15

What is the rate of decay …

01:47

00:51

Involve exponential decay.…

01:42

A radioactive substance ha…

01:52

The radioactive isotope ca…

00:30

The activity of radioactiv…

04:52

What is the half-life (in …

01:17

The rate constant for a ce…

00:38

05:28

If a 6.13-g sample of an i…

02:54

The radioactive isotope $^…

01:58

The half-life for radioact…

01:28

06:03

Radioactive Decay. Carbon-…

00:43

A radioactive substance un…

love. Ron, this is Ricky today, working on Problem 38. We have to determine what the half life for. The first order to K of Carbon 14 is so let's go carbon. It's in actually this election and then we have a great constant for the decay with 1.21 times 10 to the native forth per year. All right, so because we know this is first order to K, we can use our half life of 0.693 over K to get the half life. So we just plug in K. When we find a T. 1/2 is equal to five 1007 127 went to seven years. So it's video. Some people see you in the next one.

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