00:01
We need to calculate the hourly production rate of chlorine gas based on the oxidation of cl minus.
00:10
So this is the equation that would take place in the anode since cl minus is being oxidized to produce cl2 gas.
00:17
Since this is an hourly production rate, that means that we can take this on the basis of one hour.
00:26
And we can use the current that we are given to convert that.
00:32
Into coolums of electricity that we must supply.
00:36
So we know that coolums per second is amps, and we have the amount of current in amps.
00:43
So we need to first convert this time into seconds by saying that one hour is equal to 3 ,600 seconds, and then multiplying this by the current 1 .50 times 10 to the third coolums per second, and then multiply this by faraday's constant 96 ,485 coolums for every one mole of electrons.
01:19
And now based on this oxidation, we see that for every one mole of cl2 gas that we produce, we also lose two electrons...