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What is the hybridization of the central atom in each of the following?(a) $\mathrm{BeH}_{2}$(b) $\mathrm{SF}_{6}$(c) $\mathrm{PO}_{4}^{3-}$(d) $\mathrm{PCl}_{5}$
a) In BeH, beryllium atom is attached to two hydrogen atoms by single bonds and it does not have any lone pair. Thus according to the data provided in the above table, the central atom of BeH, is $s p$ hybridized.b) In $\mathrm{SF}_{6}$ , sulphur atom is attached to six fluorine atoms by single bonds and it does not have any lone pair. Thus according to the table, the central atom is $s p^{3} d^{2}$ hybridized.c) In $\mathrm{PO}_{4}^{3-}$ , phosphorous atom is attached to three oxygen atoms by single bonds and one oxygen atom with double bond. It does not have any lone pair. Thus according to the data given in the above table, the central atom is $s p^{3}$ hybridized.d) In $\mathrm{PCl}_{5}$ , phosphorous atom is attached to five chlorine atoms by single bonds. It does not have any lone pair. Thus according to the table, the central atom is $s p^{3} d$ hybridized.
Chemistry 101
Chapter 8
Advanced Theories of Covalent Bonding
Chemical Bonding
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came So bonding between B H two should be very similar to the bounding in P E. C. L two is mentioned in the textbook. Where be H two forms to be h bound? We the molecule. So because off the two Covalin Bounds issued being A S P hybridization for the next one as f six, if we draw the structure, we know that as F six is founded, the sulfur is bonded to six flooring atoms. So because all of the six bounding Sze wee no issue being the S S P three d too hybridization Okay, foresee P 043 miners. It seems to be a little bit tricky, but if we draw the Louis structure out, we know that the ah force thing Adam is bonded 24 oxygen molecules, um, for oxygen at hoops and has no additional long electron pairs. So issue being as peace three hybridization orbital okay for problem number for problem t, he is co violently pounded to five coloring Adams. So's abounding well be as p three things
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