00:01
All right so we're asked what is the hydrogen ion concentration of a 2 molar solution of 2 ,6 -dinitrobenzoic acid? that's a weak acid.
00:10
I'm just still going to represent that as ha.
00:13
So this is what i have where ha represents the 2 ,6 -dinitrobenzoic acid.
00:21
If it ionizes in water you're going to have the conjugate based as the 2 ,6 -dinitrobenzoic ion which i will just represent as a minus plus hydronium ion.
00:34
Now here's the thing, initially we had 2 .00 molar of that, none of this, none of this, none of this.
00:42
So while some of this will change that will be produced and that will be produced and at equilibrium you'll have this to be 2 minus x this would be x and that would be x.
00:55
Now the ka of this right is the concentration of the conjugate base the 2 ,6 -dinitrobenzoic ion times the concentration of the hydronium ion divided by the concentration of the 2 ,6 -dinitrobenzoic acid at equilibrium...