what-is-the-impedance-of-a-150-mathrmk-omega-resistor-a-135-mathrmmh-induc-tor-and-a-228-mu-mathrmf-

Question

What is the impedance of a $1.50-\mathrm{k} \Omega$ resistor, a $135-\mathrm{mH}$ induc-
tor, and a $22.8-\mu \mathrm{F}$ capacitor connected in series with a $60.0-\mathrm{Hz}$ ac
generator?

João Gabriel Alencar Caribé · Accepted Answer

in these questions, we have to complete the impedance off that R L C circuit. So to complicate the impedance, we have to complete both reactors first. And we begin by copulating the capacity reactors, which is given by one divided by two pi times the frequency times, the capacitance and blinking in the values given by the problem. We have two pi times 60 times 22.8 times 10 to the minus six, and this is all under one. And this is approximately 116 goals. Now we complete the inductive reactors, which, even by two why times the frequency times they looked at us and its Sequels to two pi times 16 times 135 times 10 to the minus three and disease approximately 50.9 homes. Now we are in position to copulate impudence, which, given by the square root off the resistance squared, plus the difference between the reactor NCIS squared and these these equals to the square root off 1.5 understand to the third squared plus 116 minus 51 9 squared and usually is approximately 15 Who won owns, which can be further approximated to 1.5. Keeler warms

Yaqub Khan · Answer

expression for impotence off RCs. Every circuit is imprudence. Equal toe singled off. So get off registers plus so good off. But the evidence off get Mr s Reluctance off campus, sir, is equal to one A bomb Omega Psi and as Anglo Afrikaans musical toe to buy f So this use US returns is equal toe one divided by to buy f into get distance. So this use us impotence equal toe are secure Bless one of on for by sicker, absolute Here. See, it&#x27;s a girl now. Why Palladian? Different values here. Read distance Other stories 300 on plus one divided by four by a secure frequency of sources 159 hers in tow. Get distance off that Give my studies 2.5 Migra fettered, which they goingto 2.5 times 10 to the power minus six bettered. So this gives us impotence of the circuit Equal toe 500. Oh, there is an answer

João Gabriel Alencar Caribé · Answer

the impudence off that circuit is given by Z opposed to this square root off there is a distance squared. Plus you reacted squared. We have the resistance already, So the impotence is. He goes to the square root off 65.5 squared, plus the reactor&#x27;s squared, the reactant CE he&#x27;s given by one divided by two pi times the frequency times the capacitance, which in our case, use equals to one divided by to pipe time. 60 times 85. My group for it. Two. Our evidence is equal to the square. Root off 65.5 squared plus too high times 60 times, 85 times. Stand to the minor. Six under one. It&#x27;s queer, and these is approximately 73 hose.

Donald Albin · Answer

I could draw this so that we could add it up graphically. But in the end, the impedance is the square root of R squared plus x l minus X c squared. So the square root of 50 squared Plus, we have to capacitors. So negative x c at sea capacitance is, uh, one over Omega psi. It&#x27;s gonna be one over to hi. F times five Micro Farage&#x27;s 1/2 pi f ah, 10 Micro Fareed&#x27;s 10 times tended negative. Sixth. Okay. Going to erase the F six. They&#x27;re not numbers. All right. Small F to the frequency is 2000 hurts. So wherever I cf down here, I&#x27;m gonna put in 2000 so I&#x27;m just going to put that into a calculator. Square Roots of 50 squared. Now, the negatives going to cancel out. So I&#x27;m not even gonna put that in. I&#x27;m gonna put 1/2 by f is 2000 um, times five times, 10 to the negative. Six power plus 1/2 high times. 2000 end times 10 to the negative. Six power. Now, probably because I ran out of room. I forgot to write my square here, so I do have to square that. All right, that gives me 55.4, But when you rounded to two significant digits, you get 55. Oh!

Mayukh Banik · Answer

the ambulance is given by C equals quelled off R squared, thus X as minus X C squared. It was squared off are spoiled miners plus X and these omega l minus X sees a one over. We&#x27;ll make a C squared using R equals 12.5. Home is it was to be born six times 10 to the minus three. Henry GaPacif does ECOWAS five times 10 to the minus six fatty food. Omega equals Dubai F and F. It was 15 90 hards. We find that the Dora the imprint Z comes out to be 20.3. Oh, now the power factor. He&#x27;s well signed. Fee equals as are over Z. It was 12 point She was born five old, divided by 20.3 aub. It was 0.617 and the face angles fii ik was poolside in divorce, Jiraporn 617 equals 51 0.9 degree

João Gabriel Alencar Caribé · Answer

the relation between the aromas, voltage and the Aramis current is the following. The IRA man&#x27;s voltage is he goes to the Ari Mass. Current times impudence. And in the situation, the impedance has two contributions. Contribution coming from the resister, which is R squared, and another contribution coming from the doctor, which is two pi frequents times in luck tints squared. Then we can solve this equation for the current to get i r. A mass is equals two. The square root off our square plus to buy f l squared This is all under the voltage the your mess Now we can plug in the values given by the problem to get ah, you&#x27;re a mess is equals two the square root off 5 25 squared Plus to buy times the frequency 60 time thing Look tense 295 merely Henry squared and this is all under the voltage which is equal to 20. And finally this is approximately 0.37 to 6, which can be written as 37.3. I really am Piers

Problem

Consider the circuit shown in Figure 24-34. The a…

Problem 50 Easy Difficulty

What is the impedance of a $1.50-\mathrm{k} \Omega$ resistor, a $135-\mathrm{mH}$ induc-
tor, and a $22.8-\mu \mathrm{F}$ capacitor connected in series with a $60.0-\mathrm{Hz}$ ac
generator?

Answer

see work

Related Courses

Physics

Related Topics

Discussion

Top Physics 102 Electricity and Magnetism Educators

Elyse G.

Aspen F.

Jared E.

Meghan M.

Physics 102 Electricity and Magnetism Courses

Electric Charge

The Electric Force

Recommended Videos

Watch More Solved Questions in Chapter 24

Video Transcript

James S. Walker

Physics

Elyse G.

Aspen F.

Jared E.

Meghan M.

Electric Charge

The Electric Force

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

see work

Physics

Elyse G.

Aspen F.

Jared E.

Meghan M.

Electric Charge

The Electric Force

James S. WalkerPhysics

Elyse G.

Aspen F.

Jared E.

Meghan M.

James S. Walker

Physics