What is the major product of electrophilic addition of HBr to the following alkene? Explain your

step 1 Alken which we have given has the following structure. So we have Benzine rings and now one of t

What is the major product of electrophilic addition of HBr...

Key Concepts

Carbocation Stability

Carbocation stability plays a critical role in determining the major product in electrophilic additions. The reaction pathway that produces the more stable carbocation (often more substituted) is generally favored because such intermediates lower the activation energy of the reaction. This concept connects directly with Markovnikov's rule and provides insight into the regioselectivity observed in these reactions.

Markovnikov's Rule

Markovnikov's rule is used to predict the regiochemistry of electrophilic addition reactions. It states that in the addition of HX to an unsymmetrical alkene, the proton will add to the carbon with more hydrogen atoms already attached, leading to the formation of the more stable carbocation. This rule is crucial for determining which product will be predominant.

Electrophilic Addition Reaction Mechanism

This reaction type involves the addition of an electrophile to a double bond where the alkene acts as a nucleophile. The process typically proceeds through the formation of a carbocation intermediate after the initial attack by the proton (H+), followed by the capture of a nucleophile (like Br–). Understanding this mechanism is fundamental for predicting reaction outcomes in organic chemistry.

Transcript

00:01 Alken which we have given has the following structure.

00:04 So we have benzine rings and now one of the benzine ring consists of n -o -2 group.

00:19 So this n -o -2 group can be drawn like this.

00:27 And now i have the double bond here and now this is further attached to another ben -o -2 ring then i have och3 okay so now here in this reaction two kind of carboketions can form so one case case first so in that now i have this carbon here okay this carbon is directly attached to this ring and this ring is further attached to this n -oto group this no2 group is electron withdrawing in nature, right? so it will deactivate the string.

01:20 It will de -staplyze the carbocation formed.

01:24 Okay.

01:25 So here, due to electron withdrawing nature of no2, so carboketion is deist.

01:56 Step live.

02:03 So now let me show you how.

02:07 So i have hbr here.

02:12 Okay.

02:13 So now in this hbr, this br is electron negative.

02:19 It will have partial electron density over itself.

02:23 It will withdraw all the electron towards itself being electronegative and it has partial negative charge.

02:31 This hydrogen being attached to electronegative atoms so it's all electron are being withdrawn and for this reason it will have partial positive charge so what will happen that this h positive ion will remove from here when this h positive ion being removed from here so then here i have this double bond this is here electron rich center so this is how carbucatin will form now so i have this electron which center double bond and this will attach on this h -positive ion.

03:06 So now what will happen here? that carboketion will form like this.

03:14 So i have this benzene ring and i have this nitrogen atom, oxygen atom and now it carries positive charge over itself and double bonded oxygen atom.

03:46 And now so i have this hydrogen atom here attest to another ring and now och3 okay and here we will have this positive charge okay so this is the carbocatine so how did this happen so now here there can be delocalization of bonds okay so so now you can see that these arrows are showing that this anode group are withdrawing the electrons.

04:37 So you can see that the electron density over itself.

04:41 So that is reducing.

04:42 So this carbocatin is de -stabilizing here.

04:46 So this is what we want to say here that the carbocetion is destabilized because the ring which this carbocatine is attest, that ring is further...

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