00:01
So this problem gives us a number of moles of a certain element and wants us to find the number of grams from that number of moles.
00:08
And so to do that, we'll just multiply by the molar mass given on the periodic table.
00:14
And so letter a is 2 .3 times 10 to the negative third moles of antimony, sb.
00:23
So we multiply that by its molar mass, which is 121 .76 grams per mole.
00:29
The moles cancel and we end up with 0 .28 grams of sb and that's our final answer for letter a.
00:39
Now we do the same thing for the rest of these.
00:41
So for letter b, we have 0 .355 moles of barium b .a.
00:49
We multiply by barium's molar mass, which is 137 .33 grams per mole.
00:56
And that gives us, again, moles cancel...