- Volume of buffer solution = $80.0 \mathrm{~mL} = 0.0800 \mathrm{~L}$
- Molarity of $\mathrm{NH}_3$ = $0.169 \mathrm{M}$
- Moles of $\mathrm{NH}_3$ = Molarity Ă— Volume = $0.169 \mathrm{M} \times 0.0800 \mathrm{L} = 0.01352 \mathrm{~mol}$
- Molarity of
Show more…