What is the $\mathrm{pH}$ of $4 \times 10^{-3} \mathrm{M}-\mathrm{Y}(\mathrm{OH})_{2}$
solution assuming the first dissociation to be $100 \%$ and second dissociation to be $50 \%$, where $Y$ represents a metal cation? $(\log 2=0.3, \log 3=0.48)$
(a) $11.78$
(b) $11.22$
(c) $2.22$
(d) $2.78$