00:02
Hello there.
00:03
For this problem, they want to know what is the ph of a solution prepared by dissolving 2 .5 grams of hydrochloric acid and water to make 425 millimeters of solution.
00:19
So how we're going to solve for the ph that we would need to do a negative log times h3l plus.
00:34
Us to get that because it's in molarity that we will need moles over liters problem we have grams over here and another problem we have milliliters so we're going to do some conversion to get this part to also use that to get this part so let's start off with converting these to get them both set up for the molarity part so let's start with the grams so how we do that is is we get 2 .5 grams of the given, we use the given problem, and we're going to define it by the molar mass, the molecular mass of hydrochloric acid.
01:21
In doing so, we get 0 .069.
01:25
And then when we do a conversion for milliliters, we just divide by 1 ,000 milliliters to get one liter.
01:31
And that's why we get 0 .425.
01:35
And we do this, you can think about that.
01:36
King henry die basically drinking chocolate milk.
01:46
So since this is milliliters, you just go about one, two, three.
01:50
So that's just one way you could just do like that, one, two, three.
01:54
And that's how you get that...