Question
What is the molar concentration of As(III) in a solution if 22.35 $\mathrm{mL}$ of 0.100 $\mathrm{M} \mathrm{KBrO}_{3}$ is needed for complete reaction with 50.00 $\mathrm{mL}$ of the As (III) solution? The balanced equation is:$$3 \mathrm{H}_{3} \mathrm{AsO}_{3}(a q)+\mathrm{BrO}_{3}^{-}(a q) \longrightarrow \mathrm{Br}^{-}(a q)+3 \mathrm{H}_{3} \mathrm{AsO}_{4}(a q)$$
Step 1
We know that 1 liter is equal to 1000 milliliters, so we have: $$22.35 \, \mathrm{mL} \times \frac{1 \, \mathrm{L}}{1000 \, \mathrm{mL}} = 0.02235 \, \mathrm{L}$$ Show more…
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