Question
What is the molar entropy of a pure crystal at $0 \mathrm{~K}$ ? What is the significance of the answer to this question?
Step 1
According to the Third Law of Thermodynamics, the molar entropy of a pure crystal at 0 K is zero (S = 0 J/mol·K). Show more…
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(a) What is the entropy of a perfect crystal at 0 $\mathrm{K}$ ? (b) Does entropy increase or decrease as the temperature rises? (c) Why is $\Delta H_{\mathrm{f}}^{\circ}=0$ but $S^{\circ}>0$ for an element? (d) Why does Appendix $\mathrm{B}$ list $\Delta H_{\mathrm{f}}^{\circ}$ values but not $\Delta S_{\mathrm{f}}^{\circ}$ values?
The third law of thermodynamics says that a perfect crystal at 0 K has zero entropy. The standard entropy of a substance, $S^{\circ}$ can be determined by evaluating the energy required to carry out conversion from 0 K to standard conditions. What information would be needed to calculate $S^{\circ}$ for liquid water at $298 \mathrm{K}$ and 1 bar?
The third law of thermodynamics states that the entropy of a perfect crystal at 0 $\mathrm{K}$ is zero. In Appendix $4, \mathrm{F}^{-}(a q), \mathrm{OH}^{-}(a q)$ and $\mathrm{S}^{2-}(a q)$ all have negative standard entropy values. How can $S^{\circ}$ values be less than zero?
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