Question
What is the molarity of standard sulfuric acid if $27.75 \mathrm{~mL}$ of $\mathrm{H}_{2} \mathrm{SO}_{4}$ neutralizes $1.000 \mathrm{~g}$ of sodium hydrogen carbonate?$$\begin{aligned}\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{NaHCO}_{3}(a q) & \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{CO}_{2}(g)\end{aligned}$$
Step 1
We do this by dividing by 1000: $$ \text{Volume of } \mathrm{H}_{2} \mathrm{SO}_{4} = \frac{27.75 \, \text{mL}}{1000} = 0.02775 \, \text{L} $$ Show more…
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