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University of Toronto

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Problem 41

What is the molecular formula of each compound?

(a) Empirical formula $\mathrm{CH}(\mathscr{M}=78.11 \mathrm{g} / \mathrm{mol})$

(b) Empirical formula $\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}(\mathscr{M}=74.08 \mathrm{g} / \mathrm{mol})$

(c) Empirical formula $\mathrm{HgCl}(\mathscr{M}=472.1 \mathrm{g} / \mathrm{mol})$

(d) Empirical formula $\mathrm{C}_{7} \mathrm{H}_{4} \mathrm{O}_{2}(\mathscr{M}=240.20 \mathrm{g} / \mathrm{mol})$

Answer

a) molecular formula= $\mathrm{C}_{6} \mathrm{H}_{6}$

b) molecular formula= $\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}$

c) molecular formula= $\mathrm{Hg}_{2} \mathrm{Cl}_{2}$

d) molecular formula $=\mathrm{C}_{14} \mathrm{H}_{8} \mathrm{O}_{4}$

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## Discussion

## Video Transcript

So we have to determine the more can phone from the empirical formula with Giffen by the mass and also empirical from there, so different between welcome foreigner and critical for formula is that Ah, Marco Fuller is a multiple for am prick off from the ethical formula. So therefore ah, the m the mother mess or empirical formula? Oh, mother. Mass of the molecule for your also based in multiple On the off, the more the mass on the empirical formula as well. Okay, so you know those who filed a mobile phone for part A. So the ethical father is see each. So from here, we can know that. Ah, um, other ass for the uniform. I was 13. So is 12 to pass one for? The more the mass of carbon and hydrogen. So we just need to take our more like your former divide by the, um more certain molecular weight. Oh, the mother mass divided by ah, every cook, ma'am. Pickle mother mass. And they were filed in multiple. So if 78.11 day went by 13 where we can find their wealth, their on six times war, So the actual um Oh, the mass is sorry. The actual market, the formula would be C 66. Okay, So same calculation can be applied to Poppy. So we have C free x 602 for the market performer and then for the sort for empirical phone for the marketing of the massive 74.8 So we just need to find out. Um ah, the famous off the empirical phoners over athlete Harbin 1st 6 oxygen was too Ah, oxygen. So we'll be a 74 and you can see that they were off. The hunters say meth. I mean this with the masses. What the equals to the, um, molecular move by the mass. So therefore, how their mobile will be re arm one. So we have stare safely xx Ooo to as the molecular formula. Okay, so in with phones, you see a game just to find out. Ah, temple with the mass of the empirical phoner. So we have a mercury. Ah, we've ah core Cora. Car, car, car. Right. So to 1st 6.5 Grandpa removal at Brickell formula. So we're going to take our molecule further divided by our, um, chemical formula so roughly around two. So we know that the actual want Griffo Notorious G to see out too. Okay, so the last one we have sees Evan ex forwards you and there's 24 year points. You, Graham, for more again, which is you. Find out the, um other myself. This for me there two time 16 we have won 20 Grant Trimble and you can see that's what we have around two times more for them or more on the massive, somewhat more killer formula. So from here, we can see that I see 7 14 h 604 for the Balkan formula.

## Recommended Questions

What is the molecular formula of each compound?

(a) Empirical formula $\mathrm{CH}_{2}(M=42.08 \mathrm{g} / \mathrm{mol})$

(b) Empirical formula $\mathrm{NH}_{2}(\mathscr{M}=32.05 \mathrm{g} / \mathrm{mol})$

(c) Empirical formula $\mathrm{NO}_{2}(\mathscr{M}=92.02 \mathrm{g} / \mathrm{mol})$

(d) Empirical formula CHN $(M=135.14 \mathrm{g} / \mathrm{mol})$

The empirical formula and molar mass of several compounds are listed. Find the molecular formula of each compound.

a. C6H7N, 186.24 g>mol

b. C2HCl, 181.44 g>mol

c. C5H10NS2, 296.54 g>mol

The molar mass and empirical formula of several compounds are listed. Find the molecular formula of each compound.

a. C4H9, 114.22 g>mol

b. CCl, 284.77 g>mol

c. C3H2N, 312.29 g>mol

Determine the empirical formula for the compound represented by

each molecular formula.

$$

\text { a. }\mathrm{C}_{2} \mathrm{H}_{4} \quad \text { b. } \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \quad \text { c. } \mathrm{NH}_{3}

$$

Give the empirical formula that corresponds to each molecular formula.

(a) $\mathrm{C}_{2} \mathrm{H}_{6}$

(b) $\mathrm{N}_{2} \mathrm{O}_{4}$

(c) $\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}$

(d) $\mathrm{NH}_{3}$

The molar masses and empirical formulas of several compounds containing carbon and nitrogen are listed here. Find the molecular formula of each compound.

(a) $163.26 \mathrm{g} / \mathrm{mol}, \mathrm{C}_{11} \mathrm{H}_{17} \mathrm{N}$

(b) $186.24 \mathrm{g} / \mathrm{mol}, \mathrm{C}_{6} \mathrm{H}_{7} \mathrm{N}$

(c) $312.29 \mathrm{g} / \mathrm{mol}, \mathrm{C}_{3} \mathrm{H}_{2} \mathrm{N}$

Determine the empirical formula for the compound represented by each molecular formula.

a. N2O4

b. C5H12

c. C4H10

Write the empirical formula corresponding to each of the following molecular formulas: (a) $\mathrm{Al}_{2} \mathrm{Br}_{6},(\mathbf{b}) \mathrm{C}_{8} \mathrm{H}_{10}$ (c) $\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{2},(\mathbf{d}) \mathrm{P}_{4} \mathrm{O}_{10},(\mathbf{e}) \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{Cl}_{2},(\mathbf{f}) \mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6} .$

Determine the molecular formulas to which the following empirical formulas and molar masses pertain.

a. SNH (188.35 g/mol)

c. $\mathrm{CoC}_{4} \mathrm{O}_{4}(341.94 \mathrm{g} / \mathrm{mol})$

b. $\mathrm{NPCl}_{2}(347.64 \mathrm{g} / \mathrm{mol})$

d. $\mathrm{SN}(184.32 \mathrm{g} / \mathrm{mol})$

What is the molecular formula of a compound with an empirical formula of $\mathrm{B}_{2} \mathrm{H}_{5}$ and a molar mass of $53.2 \frac{\mathrm{g}}{\mathrm{mol}} ?$

A. $\mathrm{B}_{2} \mathrm{H}_{5}$

B. $\mathrm{B}_{3} \mathrm{H}_{7}$

C. $\mathrm{B}_{4} \mathrm{H}_{10}$

D. $\mathrm{B}_{6} \mathrm{H}_{15}$