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What is the near point of a person whose eyes have an accommodated power of 53.5 D?

28.6 $\mathrm{cm}$

Physics 103

Chapter 26

Vision and Optical Instruments

Reflection and Refraction of Light

Wave Optics

Cornell University

Simon Fraser University

University of Winnipeg

McMaster University

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near point off, the person means distance to the object. D'oh! We confined Ah d'oh By using a formula, power is equal to one or distance the object plus one over distance to the image, then solving for dio distance to the object we get P minus one more distance to the image. Why this one? Then Simply cool substrate values from the given problem that is our rehab is a 53 when five doctors minus one were distanced. Image we have is important 02 meters so whole minus one. Simplifying this expression gives us ah distressed object or a near point is point is it two It six majors or in centimeters 28.6 centimeters.

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