00:02
Here in this problem, we have to find oxidation number of carbon in each of the following compounds.
00:10
First one is co, carbon monoxide.
00:14
Let the oxidation number of carbon bx, x plus one oxygen, that is oxidation number of oxygen in its compound is negative 2.
00:27
And the sum of the oxidation number of all the atoms in a species is equal to the net charge on the species.
00:38
Here, net charge is zero, so the sum will be zero.
00:42
Therefore, x will be equal to positive two.
00:46
So the oxidation number of carbon in co is plus 2.
00:55
Then co2, x, oxidation number for carbon, two oxygen atoms 2 times negative 2 is equal to the net charge on carbon dioxide zero, no charge, so it is 0.
01:10
Therefore, x will be positive 4.
01:14
Therefore, oxidation number of carbon in co2 is positive 4.
01:23
Then ch4.
01:26
Let the oxidation number for carbon be x plus four times positive 1.
01:33
One positive 1 is the oxidation number of hydrogen in this compound is equal to the net charge on the species which is 0...