Question
What is the oxidation state of Fe in the product formed when acidified potassium ferrocyanide is treated with $\mathrm{H}_{2} \mathrm{O}_{2} ?$(a) $+2$(b) $+6$(c) $+1$(d) $+3$
Step 1
When it is acidified, it forms H4[Fe(CN)6]. Now, let's consider the reaction with H2O2 (hydrogen peroxide). The reaction can be written as: H4[Fe(CN)6] + H2O2 → [Fe(CN)6] + 4H2O In this reaction, hydrogen peroxide acts as an oxidizing agent, and the oxidation Show more…
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