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What is the oxidation state of the halogen in each of the following?(a) $\mathrm{H}_{5} \mathrm{IO}_{6}$(b) $\mathrm{IO}_{4}-$(c) $\mathrm{ClO}_{2}$(d) $\mathrm{ICl}_{3}$(e) $\mathrm{F}_{2}$

a. $+7$b. $+7$c. $+4$d. $+3$e. 0

Chemistry 101

Chapter 18

Representative Metals, Metalloids, and Nonmetals

Nonmetals Chemistry

Rice University

University of Kentucky

University of Toronto

Lectures

04:44

What is the oxidation stat…

02:35

04:40

Name the following compoun…

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01:45

Determine the oxidation st…

05:11

let us consider the oxidation state off. I Odin be X. The compound overall has no oxidation state. That is right towards the right inside off equation, We have zero oxidation. State off hydrogen. It's plus one. By that off. Oxygen is negative. Toe soaring The equation the value off ex turns out to be plus seven, which is oxidation. State off irony for option B the oxidation state off. I didn't be x by that off. Oxygen B minus tow The overall oxidation stayed off. The compound is negative one. That is why towards the right inside off equation, we have minus one solving this equation The oxidation state off Aidan comes out Toby plus seven for option C the oxidation state off chlorine BX and oxygen B minus two over a lecture. Overall oxidation state off. Compounded zero. Solving the equation The oxidation state off. Loneliness plus four for option B oxidation State off Aydin is X so that off chlorine B minus one. The overall oxidation state of compound zero. So solving the equation, the oxidation state off fired in this plus tree in case off Lauren the oxidation state off Florian B x on the overall compound that charge overall compound net oxidation state is also to you. Hence the oxidation state off Lauren in F two molecule is zero.

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