00:02
So we're going to start with all the information that's been provided.
00:06
So we know that benzoyic acid, its volume is 50m.
00:10
And its concentration is 0 .0 .15 molar.
00:14
And k -o -h, the volume is 30m.
00:16
And concentration is 0 .0 .15 molar.
00:19
So with this information, we're going to calculate the number of molds for each of this.
00:27
So molds is equal to 0 .05 divided by 0 .015.
00:37
That gives us 1, 2, 3, 75 moles.
00:47
Similarly, for k -o -h, volume divided by concentration, that gives us 1, 2, 3, 4, 5 months.
01:07
Now for the reaction, pentoic acid is c6, h5, c -o -o -h, plus o -h -h -mine, if c6 h5 c0 minus plus h2o minus plus h2 o so now the change in uh...
01:53
Mold after reaction for benzoyic acid would be one two three seven five minus four five so that is point zero three molds which is for benzoic acid and for c six change in equal to 0 .45 moles.
02:58
Now to calculate new concentrations, we know that the total volume here is 50 ml plus 30m.
03:23
And liters that is 0 .08 liters.
03:31
So we're going to calculate in with each of the changes.
03:36
We're going to calculate the moles per liter...