Question
What is the position uncertainty, in $\mathrm{nm}$, of an electron whose velocity is known to be between $3.48 \times 10^{5} \mathrm{m} / \mathrm{s}$ and $3.58 \times$ $10^{5} \mathrm{m} / \mathrm{s} ?$
Step 1
In this case, it is $3.58 \times 10^{5} \mathrm{m} / \mathrm{s}$ - $3.48 \times 10^{5} \mathrm{m} / \mathrm{s}$ = $1 \times 10^{4} \mathrm{m} / \mathrm{s}$. Show more…
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