What is the rate of entropy increase in Problem 12.9 ? |...

Name: Problem 10, Chapter 12: Fundamentals of Thermodynamics
Uploaded: 2020-08-20T16:45:18-08:00
Duration: 6 min 26 s
Channel: Sarah Mccrumb
Description: What is the rate of entropy increase in Problem 12.9 ?

Key Concepts

Entropy

Entropy is a fundamental measure of disorder or randomness in a system, quantifying the number of microscopic configurations corresponding to its macroscopic state. It plays a central role in thermodynamics by indicating how energy is dispersed in a system and is intimately related to the concept of irreversibility in natural processes.

Second Law of Thermodynamics

The Second Law of Thermodynamics establishes that the total entropy of an isolated system can only increase over time, or remain constant in ideal cases where reversible processes occur. This principle is essential for understanding the direction of spontaneous processes and the eventual approach to equilibrium.

Entropy Production

Entropy production refers to the rate at which entropy is generated within a system due to irreversible processes. It provides a quantitative measure of the inefficiencies in energy transformations and dissipative effects occurring when a system deviates from equilibrium.

Rate of Entropy Increase

The rate of entropy increase is a dynamic measure used to assess how quickly the entropy of a system changes over time. This concept is particularly important in non-equilibrium thermodynamics, where it helps to characterize the system's progression towards equilibrium and to evaluate the impact of external and internal processes on its evolution.

Transcript

00:01 Hi, everybody.

00:01 So we need to find what is the rate of entropy increase in problem 12 .9, which was, so for this, we need, we have the energy equation.

00:14 So in the original one, and we had, and i'm actually just going to write it out lengthwise.

00:23 So, and we had mr, c, p of argonne times t1 plus m -c -o -2, c -p of co2, t1, okay, equals, and we go take out t2, and we have m -a -r plus c -p -o -2 times c -p -a -r plus m -c -o -2 times c -p -c -o -2.

00:54 Okay, and from this we had one at times 0 .52 times 300 plus one times 0 .842 2 times 16 ,000 equals you had t2 out and we had 1 times 0 .52 plus 1 times 0 .52 plus 1.

01:28 Times 0 .842.

01:34 Okay.

01:36 And so your t2 is 1103 .67k.

01:43 And we found that your pressure was 150k pascals.

01:47 And that was given in problem nine.

01:51 Okay.

01:53 So we didn't really have to do any math for that.

01:55 And now for your, we need to find a rate of entropy increase.

02:04 So from this, we have entropy equals m -a -r and we have c -p -a -r times the log of your exit versus your initial.

02:22 Okay, temperature.

02:23 And we have the rate of argarn times the log of the one.

02:29 Y -a -r of argon times the p -a and the exit.

02:36 And this is going to be plus, and we're just going to scroll down a little bit.

02:40 And we have the mass of the co2 times cp of co2 times the log of the exit temperature times the initial temperature minus the rate of co2 times log.

03:00 Of y of co2 times the pressure exit and the pressure initial.

03:10 Okay, and now we just need to find the y of a .r...

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