What is the solubility product of $\mathrm{Al}(\mathrm{OH})_{3}$ in water. Given:
$\mathrm{Al}(\mathrm{OH})_{4}^{-}(\mathrm{aq}) \rightleftharpoons \mathrm{Al}^{3+}(\mathrm{aq})+4 \mathrm{OH}^{-}(\mathrm{aq})$
$K=1.3 \times 10^{-34}$
$\mathrm{Al}(\mathrm{OH})_{3}(\mathrm{~s})+\mathrm{OH}^{-}(\mathrm{aq}) \rightleftharpoons \mathrm{Al}(\mathrm{OH})_{4}^{-}(\mathrm{aq}) ;$
$K=38.5$
(a) $3.1 \times 10^{-35}$
(b) $5 \times 10^{-33}$
(c) $6.1 \times 10^{-33}$
(d) $5 \times 10^{-34}$