Question
What is the specd of the particle when its $y$ -coordinate becomes $84 \mathrm{~m}$ ?(a) $48 \mathrm{~m} / \mathrm{s}$(b) $37.3 \mathrm{~m} / \mathrm{s}$(c) $26.5 \mathrm{~m} / \mathrm{s}$(d) $25.6 \mathrm{~m} / \mathrm{s}$
Step 1
We can use this information to find the time at which the particle reaches this position. From the second equation, we have $y = t^2$. Substituting $y = 84$ m, we get $t = \sqrt{84}$. Show more…
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1. What is $y$ -coordinate of the particle at the instant its $x$ -coordinate becomes $84 \mathrm{~m}$ ? (a) $84 \mathrm{~m}$ (b) $56 \mathrm{~m}$ (c) $48 \mathrm{~m}$ (d) $36 \mathrm{~m}$
Motions in Two and Three Dimensions
Section C
What is the $y$ -coordinate of the particle at that time? (a) $24 \mathrm{~m}$ (b) $20 \mathrm{~m}$ (c) $16 \mathrm{~m}$ (d) $18 \mathrm{~m}$
A particle starts from origin at $t=0$ with a velocity $5 \hat{i} \mathrm{~m} \mathrm{~s}^{-1}$ and moves in $x-y$ plane under the action of a force which produces a constant acceleration of $3 \hat{i}+2 \hat{j} \mathrm{~m} \mathrm{~s}^{-2}$. The $y$-coordinate of the particle at the instant when its $x$-coordinate is $84 \mathrm{~m}$ is (a) $12 \mathrm{~m}$ (b) $24 \mathrm{~m}$ (c) $36 \mathrm{~m}$ (d) $48 \mathrm{~m}$
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