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What is the standard enthalpy of formation for a compound? For a pure element in its standard state?
$697-06-26 \mathrm{RQ} \mathrm{SA}-9877$$\mathrm{SR} : 5276$Standard enthalpy of formation $\left(\Delta H_{f}^{0}\right)$$\cdot$ For a pure compound: The change in enthalpy when 1 mole of the compound forms from itsconstituent elements in their standard states.$\cdot$ For pure Element in its standard state; $\Delta H_{f}^{0}=0$
Chemistry 102
Chemistry 101
Chapter 9
Thermochemistry
Thermodynamics
Chemical reactions and Stoichiometry
Carleton College
Rice University
Drexel University
Brown University
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So this question asks, What is the standard entropy of formation? And so this little circle here means that it's standard, and that means it's in its standard state. So ah, standard temperature and pressure as defined as to ninety eight Calvin and one atmosphere on Behalf stands for formation. And so what this is is the change in entropy off one mall of substance being formed from its pure elements. And so if we have the Delta H of formation of H two o, that's the delta H of ah, reaction from the reaction H plus age plus oh form's H two o. And so Ah, that is how this Delta H standard entropy in formation is ah is found. And so if you were to do this of a pure element, it's equal to zero so of a molecule. It's equal to forming that molecule from its pure elements. But for a pure element zero
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