Question
What is the time for one complete revolution for a very high-energy proton in the $1.0-\mathrm{km}$ -radius Fermilab accelerator?
Step 1
The formula for the circumference of a circle is $2\pi r$, where $r$ is the radius of the circle. In this case, the radius of the rotation is 1 kilometer, or $10^3$ meters. Show more…
Show all steps
Your feedback will help us improve your experience
Jacob Shpiece and 84 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
(I) What is the time for one complete revolution for a very high-energy proton in the 1.0-km-radius Fermilab accelerator?
ELEMENTARY PARTICLES
High-Energy Particles and Accelerators
(1) What is the time for one complete revolution for a very high-energy proton in the 1.0 -km-radius Fermilab accelerator?
A proton in Fermilab's Tevatron is accelerated through a potential difference of 2.5 MV during each revolution around the ring of radius $1.0 \mathrm{km} .$ In order to reach an energy of 1 TeV, how many revolutions must the proton make? How far has it traveled?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD