Question
What is the value of Peltier coefficient for thej unction of the given thermocouple at temperature $20^{\circ} \mathrm{C}$ ?(a) $2.1 \mathrm{mV}$(b) $4.2 \mathrm{mV}$(c) $6.3 \mathrm{mV}$(d) $8.4 \mathrm{mV}$
Step 1
Step 1: Given the thermoelectric EMF (E) can be written as \[E = AT + \frac{1}{2}B(T-273)^2\] where A and B are constants, and T is the temperature in Kelvin. Show more…
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The value of Peltier coefficient of a thermocouple: (a) does not vary with absolute temperature of the junction (b) varies with absolute temperature of the junction (c) does not depend on the two different metals forming the junction (d) varies with the direction of current
A thermocouple is formed from two different metals, joined at two points in such a way that a small voltage is produced when the two junctions are at different temperatures. In a particular iron-constantan thermocouple, with one junction held at $0^{\circ} \mathrm{C}$, the output voltage varies linearly from 0 to $28.0 \mathrm{mV}$ as the temperature of the other junction is raised from 0 to $510^{\circ} \mathrm{C}$. Find the temperature of the variable junction when the thermocouple output is $10.2 \mathrm{mV}$.
The thermo emf $E$ of a given thermocouple and 78 temperature $\theta$ of the hot junction (with cold junction at $0{ }^{\circ} \mathrm{C}$ ) are found to satisfy approximately the following relation. $$ E=a \theta+\frac{1}{2} b \theta^{2} $$ where $E$ is in $\mu \mathrm{V}, \theta$ in ${ }^{\circ} \mathrm{C}$ of the hot junction and and 79 $a=14 \mu \mathrm{V}^{\circ} \mathrm{C}^{-1}$ and $b=-0.04 \mu \mathrm{V}^{\circ} \mathrm{C}^{-2}$ At what temperature, the thermo emf in the given thermocouple is $1.25 \mathrm{mV} ?$ (a) $105^{\circ} \mathrm{C}$ (b) $210^{\circ} \mathrm{C}$ (c) $315^{\circ} \mathrm{C}$ (d) $330^{\circ} \mathrm{C}$
Current Electricity
Round 2
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