Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Sent to:
  • Textbooks
  • Test Prep
  • Numerade for Schools
  • Bootcamps
  • Class
  • Ask Question
  • StudyParty
  • Earn Money
    Refer a friend. Get $50! Become an Educator
  • Log in

Problem

Hydrogen is prepared commercially by the reaction…
01:05
preview
Numerade Logo

Get the answer to your homework problem.

Try Numerade free for 7 days

Matthew H.
Numerade Educator

Like

Report

Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101

Problem 53 Medium Difficulty

What is the value of the equilibrium constant at $500^{\circ} \mathrm{C}$ for the formation of $\mathrm{NH}_{3}$ according to the following equation?
$\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)$
An equilibrium mixture of $\mathrm{NH}_{3}(g), \mathrm{H}_{2}(g),$ and $\mathrm{N}_{2}(g)$ at $500^{\circ} \mathrm{C}$ was found to contain $1.35 \mathrm{M} \mathrm{H}_{2}, 1.15 \mathrm{M}_{2},$ and 4.12 $\times 10^{-1} M \mathrm{NH}_{3}$

Answer

$6.00 \times 10^{-2}$

Related Courses

Chemistry 102
Chemistry

Chapter 13

Fundamental Equilibrium Concepts

Related Topics

Chemical Equilibrium

Aqueous Equilibria

Discussion

You must be signed in to discuss.
Top Chemistry 102 Educators
Lizabeth T.
Morgan S.

University of Kentucky

KS
Karli S.
Jake R.

University of Toronto

Chemistry 102 Courses

Lectures

Video Thumbnail

00:41
Aqueous Ionic Equilibrium - Intro

In chemistry, an ion is an…
Video Thumbnail

10:03
Concept Of Equilibrium - Overview

In thermodynamics, a state…
Join Course
Recommended Videos

00:54

At $450^{\circ} \mathrm{C}…

02:07

At $450^{\circ} \mathrm{C}…

01:00

The value of the equilibri…

01:23

Consider the reaction:
…

01:04

The equilibrium constant $…

01:10

Consider the reaction.
…

05:36

The equilibrium constant $…

07:05

The equilibrium constant $…

01:31

At $500^{\circ} \mathrm{C}…

01:50

The equilibrium constant $…

01:09

An equilibrium mixture of …

02:26

At $500 \mathrm{K},$ a $10…

04:46

For the reaction $$\mathrm…

03:39

The equilibrium constant $…

06:16

The equilibrium constant $…

04:46

For the reaction
$$\mat…

09:45

As shown in Table $15.2, K…

02:41

Determine the value of the…

04:05

Calculate the value for th…

01:03

Write the equilibrium cons…

Watch More Solved Questions in Chapter 13

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
Problem 74
Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86
Problem 87
Problem 88
Problem 89
Problem 90
Problem 91
Problem 92
Problem 93
Problem 94
Problem 95
Problem 96
Problem 97
Problem 98
Problem 99
Problem 100
Problem 101

Video Transcript

So here we're asked to consider the equilibrium between nitrogen and hydrogen gas and ammonia, and we're told that at equilibrium in a temperature of 500 degrees Celsius, the concentrations of each of these species are written down here below the equation, and they want us to calculate the value of equilibrium constant at this given temperature. What that means is that since we know that these concentrations represent the reaction vessel at equilibrium, we know that we could just write the equilibrium expression, plug these values into it and calculate the equilibrium constant. So we know that Casey is going to be equal to the concentration of products over reactions. So here we're going to have the concentration of ammonia squared, divided by the concentration of nitrogen and the concentration of hydrogen hydrogen to the third. So we're really just going to be plugging our values and for this So we're going to have a 0.412 square to the numerator, and we're going to have 1.15 times 1.35 to the third in the denominator when we multiply this through, what we find is that the equilibrium constant for this expression is six times 10 to the negative, too

We have video lessons for 98.09% of the questions in this textbook
Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson

Chemistry

View More Answers From This Book

Find Another Textbook

Related Topics

Chemical Equilibrium

Aqueous Equilibria
Top Chemistry 102 Educators
Lizabeth T.

Numerade Educator

Morgan S.

University of Kentucky

KS
Karli S.

Numerade Educator

Jake R.

University of Toronto

Chemistry 102 Courses

Lectures

Video Thumbnail

00:41
Aqueous Ionic Equilibrium - Intro

In chemistry, an ion is an atom or molecule that has a non-zero net electric…
Video Thumbnail

10:03
Concept Of Equilibrium - Overview

In thermodynamics, a state of thermodynamic equilibrium is a state in which …
Join Course
Recommended Videos

00:54

At $450^{\circ} \mathrm{C}$ the value of the equilibrium constant for the fo…

02:07

At $450^{\circ} \mathrm{C}$ , the value of the equilibrium constant for the …

01:00

The value of the equilibrium constant $K_{\mathrm{p}}$ for the formation of …

01:23

Consider the reaction:
$$\mathrm{NH}_{4} \mathrm{HS}(s) \rightleftharpoon…

01:04

The equilibrium constant $K_{\mathrm{p}}$ for the synthesis of ammonia
$$…

01:10

Consider the reaction.
$$
\mathrm{NH}_{4} \mathrm{HS}(s) \rightlefthar…

05:36

The equilibrium constant $K_{c}$ for the following reaction is 1.2 at $375^{…

07:05

The equilibrium constant $K_{\mathrm{c}}$ for the following reaction is 1.2 …

01:31

At $500^{\circ} \mathrm{C},$ the equilibrium constant $K_{\mathrm{p}}$ for t…

01:50

The equilibrium constant $K_{p}$ for the synthesis of ammonia,
$$
\mat…

01:09

An equilibrium mixture of $\mathrm{N}_{2}, \mathrm{H}_{2},$ and $\mathrm{NH}…

02:26

At $500 \mathrm{K},$ a $10.0 \mathrm{L}$ equilibrium mixture contains $0.424…

04:46

For the reaction $$\mathrm{NH}_{3}(g)+\mathrm{H}_{2} \mathrm{S}(g) \rightlef…

03:39

The equilibrium constant $K_{\mathrm{c}}$ for the reaction $2 \mathrm{NH}_{3…

06:16

The equilibrium constant $K_{\mathrm{c}}$ for the reaction
$$
2 \mathr…

04:46

For the reaction
$$\mathrm{NH}_{3}(g)+\mathrm{H}_{2} \mathrm{S}(g) \right…

09:45

As shown in Table $15.2, K_{p}$ for the equilibrium
$$\mathrm{N}_{2}(g)+3…

02:41

Determine the value of the equilibrium constant for each reaction given, ass…

04:05

Calculate the value for the equilibrium constant for each of the following a…

01:03

Write the equilibrium constant expression for the dissolution of ammonia in …

Additional Chemistry Questions
compare-the-nature-of-the-bonds-in-mathrmpbcl_2-to-that-of-the-bonds-in-mathrmpbcl_4

00:46

Compare the nature of the bonds in $\mathrm{PbCl}_{2}$ to that of the bonds …

which-of-the-following-carbonates-will-form-first-which-of-the-following-will-form-last-explain

01:06

Which of the following carbonates will form first? Which of the following wi…

explain-why-unbranched-alkenes-can-form-geometric-isomers-while-unbranched-alkanes-cannot-does-this

00:40

Explain why unbranched alkenes can form geometric isomers while unbranched a…

write-a-brief-description-or-definition-of-each-of-the-following-a-nucleon-b-alpha-particl

04:22

Write a brief description or definition of each of the following:
(a) nuc…

mtbe-methyl-tert-butyl-ether-ch_3-mathrmocleftmathrmch_3right_3-is-used-as-an

01:51

$MTBE,$ Methyl tert-butyl ether, $CH_{3} \mathrm{OC}\left(\mathrm{CH}_{3}\ri…

under-which-of-the-following-sets-of-conditions-does-a-real-gas-behave-most-like-an-ideal-gas-and-f

02:23

Under which of the following sets of conditions does a real gas behave most …

consider-a-battery-with-the-overall-reaction-mathrmcus2-mathrmaga-q-longrightarrow

00:41

Consider a battery with the overall reaction: $\mathrm{Cu}(s)+2 \mathrm{Ag}^…

from-the-data-given-in-appendix-i-determine-the-standard-enthalpy-change-and-the-standard-free-ene

01:41

From the data given in Appendix I , determine the standard enthalpy change a…

ironii-can-be-oxidized-to-ironiii-by-dichromate-ion-which-is-reduced-to-chromiumiii-in-acid-s

01:47

Iron(II) can be oxidized to iron(III) by dichromate ion, which is reduced to…

a-solution-of-0075m-cobr_ated-with-mathrmh_2-mathrmsleftleftmathrmh_2-mathrms

03:42

A solution of 0.075$M$ CoBr_ated with $\mathrm{H}_{2} \mathrm{S}\left(\left[…

Add To Playlist

Hmmm, doesn't seem like you have any playlists. Please add your first playlist.

Create a New Playlist

`

Share Question

Copy Link

OR

Enter Friends' Emails

Report Question

Get 24/7 study help with our app

Available on iOS and Android

About
  • Our Story
  • Careers
  • Our Educators
  • Numerade Blog
Browse
  • Bootcamps
  • Books
  • Topics
  • Test Prep
  • Ask Directory
Support
  • Help
  • Privacy Policy
  • Terms of Service
Get started