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What is the value of the equilibrium constant expression for the change $\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$ at $30^{\circ} \mathrm{C} ?(\mathrm{See}$Appendix E.)
0.042
Chemistry 102
Chapter 13
Fundamental Equilibrium Concepts
Chemical Equilibrium
Aqueous Equilibria
University of Central Florida
Drexel University
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University of Toronto
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A liquid is a nearly incom…
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A liquid is a state of mat…
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to hear as to consider the evaporation of water in the equilibrium between water vapor and liquid water. If you have a sample sitting, um, so one thing to remember is that the equilibrium constant for this if we were to think of it in terms of KP is just going to be interest equal to the partial pressure of water because the remember the only phases that are included in your equilibrium, expressions or gases iniquitous species. And in this case, the only side of the equilibrium that has the gaseous species is the right side. So if we go to Appendix E in the book, we find that the vapor pressure of water at 30 degrees cells Yes, it is 31.8 tour, which is equivalent to 400 or 4000 239 0.64 Pascal's and generally these equilibrium equations, as we've been learning them, are written in terms of this year's. So we're just gonna do a really quick conversion to take us from our value in Pascal's to what that would be in atmospheres. So we have again 4239.64 Pascal's we convert that by for everyone atmosphere you need 101,325 Pascal's and we will find that the equilibrium constant for the KP is going to be 0.0 for two.
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