00:01
Here is solution of 1 .20 gram naphthalene in 25 .6 gram of benzene at 23 degrees centigrade.
00:11
Vapor pressure of pure benzene at 23 degrees centigrade is 86mm mercury.
00:19
We have to find vapor pressure lowering of the solution and the vapor pressure of the solution.
00:27
Now, molar mass of naphthalene and.
00:41
And benzene are 128 .2 gram per mole and 78 .11 gram per mole respectively.
01:05
Now 1 .20 gram naphthalene is 25 .6 gram divided by the molar mass, 128 .2 gram per mole.
01:21
This will give us the number of mole of naphthalene.
01:25
That is 0 .0093603.
01:33
Then we'll find out the mole of benzene.
01:37
25 .6 gram benzene is 25 .6 gram divided by the molar mass, 78 .11.
01:50
1 gram per mole which is 0 .3277 more so total moles total mole of benzene plus naphthalene is 0 .327 plus 0 .0093603 this is the total mole now mole fraction of naphthaline more more fraction fraction of naphthalene is 0 .0093603 divided by the total mole.
02:31
3277 plus 0 .0093603...