00:03
Hello.
00:05
So the question that is asked here is related to the bohr model of an atom.
00:10
So the question is what is the wavelength of photons emitted by hydrogen atom when they undergo transition from n is equal to 4 to n is equal to 3? n is the principal quantum number and in which reason of the electromagnetic spectrum does these radiation occur? so it is like transition form if we take these as states.
00:34
So and 1 n is equal to 1, n is equal to 2, n is equal to 3, n is equal to 4.
00:43
When transition from 4 to 3 takes place, the energy emission corresponding to that can be written as e is equal to minus 13 .6 in terms of electron volt, one over final state quantum number, that is n, let us say, n f square minus 1 over an initial square.
01:08
Okay, in turn, unity is electron volts.
01:12
So that will be equal to minus 13 .6 into 1 over nf is 3 square minus 1 by 4 square.
01:23
So from here the value of energy will be minus 13 .6 into 16 minus 9 is 7 over 16 into 9 electron volt.
01:38
So we know that 11 electron volt is equal to 1 .6 into 10 to the power minus 19 in june.
01:47
Now we need to evaluate the value of wavelength.
01:50
And to evaluate the value of wavelength, let us convert this electron volts into jule.
01:57
So from here, we get the energy value is equal to minus 13 .6 into 7 over 16 into 9 into 1 .6 into 10 to the power minus 19 jule.
02:11
Okay.
02:12
This is the required value of energy.
02:14
Now take the mode of this energy.
02:16
I mean take this value positive because wavelength can never be negative.
02:20
So energy we know that can be written as hc by lambda.
02:24
That is equal to 13 .6.
02:26
This will be cancelled...