💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!

Like

Report

Numerade Educator

Like

Report

Problem 58 Easy Difficulty

What is wrong with the equation?

$ \displaystyle \int^{\pi}_{0} \sec^2 x \, dx = \tan x \Bigg]^{\pi}_{0} = 0 $

Answer

Integrand is not continuous

More Answers

Discussion

You must be signed in to discuss.

Video Transcript

Okay, let's illustrate this with the graph. As you can see, we have a definite into girls are defined for inter girls, in which the functions continuous. However, seeking squared of axes not continues on the interval. Zero pie you can see over here there. It's not continuous. There's a little bit of space in between. In other words, this space over here is pi over to. So what this means is that it's discontinuous, a pie over chip.