Question
What is wrong with the following argument? By the fundamental theorem of calculus,$$\int_{0}^{2} \frac{1}{(x-1)^{2}} \mathrm{~d} x=\left[\frac{1}{1-x}\right]_{0}^{2}=-2$$
Step 1
The given integral is: $$ \int_{0}^{2} \frac{1}{(x-1)^{2}} \mathrm{~d} x $$ Show more…
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