00:03
In the previous question, we explored the reactions of acetic anhydride.
00:11
Now let's see what would happen if we used those reagents with syssinic anhydride instead.
00:17
And it's going to be quite similar, except there's just small, tiny twists to it.
00:22
For example, our first reagent, nh3 in excess, well, previously, that would make an amide.
00:31
And in this case, it does make an amide as well.
00:33
But the problem is that the anhydride, the inhydride oxygen is in the middle of a molecule with two carboneals.
00:48
Like if we were to break it apart, those carbonyles are still on the same molecule.
00:52
It won't produce two of a molecule, it just produce one with two functional groups.
00:57
What i mean by that is that oxygen would go away and we would have two amide groups.
01:09
It would split open and we would have two amide groups present.
01:15
And that is going to be a recurring theme with these kinds of anhydride reactions.
01:23
So if we were to react this with water per se, well, we know that that hydrolyzes the inhydride, but again, the question comes which carbonyl would become a alcohol? well, the answer is both.
01:46
Both of them become sorry not alcohol carboxylacid groups and this will just be a recurring theme of what we're going to be exploring and if we were to react with an alcohol now this one doesn't say excess so it's a little bit tricky and i know i just said that this would be a recurring theme but in this case it really won't it could be if it said excess but it doesn't so really only one becomes an ester, and well, the other becomes a carbogic acid.
02:41
And you can have them flipped.
02:42
But if it said excess, then both of them would be esters.
02:48
But that is not the case.
02:52
Now, what if we had this bond to our benzene ring? now, this is once again another tricky one, right? because there's no clear place for it to bond, and it won't make a double bond or these carbons won't bond to the same carbon on the benzene...