00:01
Okay, so let's look at what we're given in the problem.
00:02
We're given 57 grams of fluorine.
00:05
We are looking for grams of cobalt.
00:08
So we are trying to find out how much cobalt would be needed to have the same number of atoms as 57 grams of fluorine.
00:17
The only way that we can figure out how much cobalt we need is to first figure out how much fluorine we have or how many moles of fluorine we have.
00:26
So besides 57 grams of fluorine, we have given the molecularity.
00:30
Molecular mass, or excuse me, molar mass of fluorine is 19 .0 grams per mole.
00:34
The molar mass of cobalts is 58 .93 grams per mole.
00:39
So if we're going to look at this, step number one is going to be trying to find how many moles of fluorine we have.
00:51
So in order to calculate your moles of you have to take the grams of f that you have which is 57 .0 grams and you are going to put that over one and then you are going to use your conversion factor to get it into moles.
01:10
Conversion factor to go from grams to moles is always molar mass.
01:15
Since we are solving for moles, one mole goes on top.
01:21
19 .0 grams goes on the bottom.
01:24
I remember when we do this, we are are going to cross off units...