Question

What mass of KMnO4 would contain 35.0 g of manganese?

   What mass of KMnO4 would contain 35.0 g of manganese?

Chemistry

Kenneth W Whitten 8th Edition

Chapter 2, Problem 78

Instant Answer

Solved by Expert Crystal Wang

09/08/2021

Step 1

We can do this by using the molar mass of Mn, which is 54.94 g/mol. This gives us: \[35.0 \, \text{g Mn} \times \frac{1 \, \text{mol Mn}}{54.94 \, \text{g Mn}}\] Show more…

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What mass of KMnO4 would contain 35.0 g of manganese?

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Key Concepts

Molar Mass

Molar mass is the mass of one mole of a substance and is used to convert between grams and moles. Knowing the molar mass of compounds like KMnO? enables one to relate the mass of the compound to the number of moles of its constituent elements.

Percent Composition

Percent composition refers to the mass percentage of each element in a compound. By calculating the percent composition of manganese in KMnO?, one can determine how much of the compound is needed to obtain a specific mass of manganese.

Stoichiometry

Stoichiometry involves the quantitative relationships between the amounts of reactants and products in chemical reactions. In problems involving compounds, these relationships allow you to use balanced formulas to convert between the mass of an element and the mass of the compound that contains it.

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