Question
What mass of solute is present in 225 mL of 0.355 M KBr solution?
Step 1
We know that 1 liter is equal to 1000 milliliters. So, we have: \[225 \, \text{mL} = 225 \times \frac{1}{1000} \, \text{L} = 0.225 \, \text{L}\] Show more…
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Solutions
Solution Composition: Normality
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