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Problem 39 Easy Difficulty

What minimum number of $75-\mathrm{W}$ light bulbs must be connected in parallel to a single $120-\mathrm{V}$ household circuit to trip a $30.0-\mathrm{A}$ circuit breaker?

Answer

48 \text { bulbs }

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Top Physics 102 Electricity and Magnetism Educators
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Video Transcript

in this problem. We are asked to kill the number of bulls and in order to kill, played this number off balls and we need to find a current passing through it. Developed using the question I want Equal Stool Petey wanted by week. Let's cool it. Equation one now setting the values into this equation we will get I want equals 2 75 What? Rewarded by 120 world. So this will give us. I want equal to 0.6 to 5 pair. No, for total current, we can write our equals two and I want but it can be a little less and equals two I divided by I want and call it equation too. Now let's ride the values off this I want and I into this equation too. We wouldn't get and equals 2 30 points here on Paddy wanted by 0.6 to 5 bad. So this will give us and equals two 48 bulbs. So and off the question

Other Schools
Top Physics 102 Electricity and Magnetism Educators
Andy C.

University of Michigan - Ann Arbor

Marshall S.

University of Washington

Zachary M.

Hope College

Jared E.

University of Winnipeg

Physics 102 Electricity and Magnetism Bootcamp

Lectures

Join Bootcamp