Problem

Which compound gives a molecular ion at $m/z$ = 1…

02:49

Problem 24 Easy Difficulty

What molecular ion is expected for each compound?

Answer

a) So the molecular formula of the compound is:- $\mathbf{C}_{\mathrm{d}} \mathbf{H}_{6}$ And the expected molecular ion of this compound is:- 78
b) So the molecular formula of the compound is: $-\mathbf{C}_{\mathbf{1} \mathbf{0}} \mathbf{H}_{16}$ And the expected molecular ion of this compound is:- 136
c) So the molecular formula of the compound is:- $\mathbf{C}_{5} \mathbf{H}_{10} \mathbf{0}$ And the expected molecular ion of this compound is:- 86
So the molecular formula of the compound is: $-\mathbf{C}_{5} \mathrm{H}_{11} \mathrm{cl}$
Chlorine has two common isotopes, $^{35} \mathrm{Cl}$ and $^{37} \mathrm{Cl},$ which occur naturally in a $3 : 1$ ratio.

Molecular formula of the compound is $\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{Cl}$ give two peaks in $3 : 1$ ratio for the molecular ion.
The larger molecular ion M peak at m/z 106$\left(\mathrm{C}_{5} \mathrm{H}_{11}^{35} \mathrm{Cl}\right)$ and the small $\mathrm{M}+2$ peak at 108 $\left(\mathrm{C}_{5} \mathrm{H}_{11}^{37} \mathrm{Cl}\right)$

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Mass Spectrometry and Infrared Spectroscopy

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Video Transcript

This is the answer to Chapter thirteen. Problem number twenty four, Fromthe Smith Organic chemistry Textbook on. So this problem is giving us five molecules and asking us where the molecular ion peak is going to be by mass spec. And so the way to approach each of these is too. Write the formula out and then do the math to figure out how much each molecule ways and that weight is where your M to Z should be. And so the first molecule is benzene is benzene on? We know benzene is C six age six. So six times twelve plus six times one I was going to add up to seventy eight. And that's where our molecular ion peak should show s o. Similarly, for be the formula is C ten h sixteen. That adds up to one hundred thirty six for sea C five h ten Oh adds up to eighty six s o for D N E. It is a little more complicated because remember, chlorine and bro mean occur in two isotopes so that the two most common isotopes are both pretty abundant. And so we'LL see the Emma Peak as well as the M plus to peek s O these molecules add up. Uh, well, so you approach them the same way. So you would write out their formula, uh, add them up, and then also add two and note that you would see both peaks. So for D, you would see a peek at one of six and a peak at Wanna wait. Similarly, for a you would see a peek at one ninety two and one ninety four, and that is the solution to prom.

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