Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

What must be the orbital speed of a satellite in a circular orbit 780 $\mathrm{km}$ above the surface of the earth?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

7.46 $\times$ 10$^3$ m/s

Physics 101 Mechanics

Chapter 6

Circular Motion and Gravitatio

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Frederick M.

November 16, 2020

Cornell University

Simon Fraser University

Hope College

McMaster University

Lectures

04:34

In physics, kinematics is the description of the motion of objects and systems in the frame of reference defined by the observer. An observer has to be specified, otherwise the term is meaningless.

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

01:54

What must be the orbital s…

01:14

what must be the orbital s…

04:48

For a satellite to be in a…

05:19

03:09

02:52

Find the orbital speed of …

02:06

The International Space St…

02:34

What is the speed of a sat…

Okay. Problem. Three fives. Action easier. Version of problem three tree. In my opinion, um, we wanted to know the speed. So this is probably 25. Want some speed of a satellite in circular bit, which is, um, 780 commoners above the surface of the earth. So if this is the earth and this is satellite, we want, ah to consider the situation. Where satellite. It's seven, 180 kilometers from the surface of the earth. So the only treating this question is that the radius off circular motion of the satellite will be the Regis of the Earth, plus seven Reaney kilometers. As we discussed in previous problem number three tree, we know that the speed of a satellite is bound to be g times m e over or but here are is equal to Regis of the Earth, plus the distance between the Earth and satellites. Here it goes. Um, so then we can right here that, uh, but the numbers in the variables subject she is 6.674 times 10 to the minus 11 with proper units. The massive earth is 5.97 times 24 kilograms and the way you have fear that R. Regis of the Earth 6.38 times, 10 to 6 meters, plus 780 kilometers which is, um, 700 80,000 meters. So meters here, meters here, meters everywhere. Kilograms. Everything's working unit wise. Um and so we get that speed crunching. All those numbers down is equal to 7000 460 meters per second. That would be 10 genital speed. So that's the spirit which goes around, of course.

View More Answers From This Book

Find Another Textbook

University of Winnipeg