What must be the volume $V$ of a $5.0$ -kg balloon filled with helium $\left(\rho_{\mathrm{He}}=0.178 \mathrm{~kg} / \mathrm{m}^{3}\right)$ if it is to lift a $30-\mathrm{kg}$ load? Use $\rho_{\text {air }}=1.29 \mathrm{~kg} / \mathrm{m}^{3}$.
The buoyant force, $V \rho_{\mathrm{air}} g$, must lift the weight of the balloon, its load, and the helium within it:
$$
V \rho_{\text {air }} g=(35 \mathrm{~kg})(g)+V \rho_{\mathrm{He}} g
$$
which gives
$$
V=\frac{35 \mathrm{~kg}}{\rho_{\mathrm{air}}-\rho_{\mathrm{He}}}=\frac{35 \mathrm{~kg}}{1.11 \mathrm{~kg} / \mathrm{m}^{3}}=32 \mathrm{~m}^{3}
$$