00:01
All right, in this question, we have a number of compounds and we're asked to find out what normal gas configuration the ions of those compounds have.
00:11
So first up, we have cesium sulfide.
00:17
So we have cs and we have sulfur.
00:22
Now we know that, you know what, we don't even need to balance this or write the empirical formula because we know the charges of these.
00:32
So cesium is going to lose an electron.
00:36
Sulfur is going to gain two electrons.
00:41
So when sulfur gains two electrons, it will reach argon configuration.
00:50
And when cesium loses an electron, it goes over here and forms the xenon configuration.
01:00
Yeah, we don't have to balance the equations or write the empirical formulas.
01:05
We can just figure out which elements there are.
01:10
So the way i solve that, if we look at sulfur, sulfur has six valence electrons.
01:19
For it to satisfy an octet, they'll need to gain two electrons.
01:26
And when it satisfies the octet, it reaches argon.
01:31
And cesium, we know that group 1a and group 2a elements like to lose their electrons.
01:37
So when cesium loses an electron, it goes to the row before, and it reaches the noble gas configuration of the row before.
01:47
Because it's just lost everything in this orbital, so it's kind of kicked off that row in terms of electrons.
01:55
All right.
01:55
So next up we have strontium fluoride.
01:58
So i'm not sure on the symbol of, i think it's st.
02:06
And i would be wrong.
02:07
It's sr.
02:08
Sr for strontium, for fluorine.
02:13
So, fluorine is over here.
02:16
We know that fluorine is the anion of this ionic bond, and we know that it's going to lose one electron.
02:22
Because it's in group, it gain one electron, because it's in group 7a, it needs one more electron.
02:27
It's going to get that electron.
02:29
So, fluorine, when it gains an electron, it reaches neon.
02:36
And strontium is an alkaline earth metal...